Integrand size = 15, antiderivative size = 258 \[ \int \frac {x^{10}}{\left (a+b x^4\right )^{3/2}} \, dx=-\frac {x^7}{2 b \sqrt {a+b x^4}}+\frac {7 x^3 \sqrt {a+b x^4}}{10 b^2}-\frac {21 a x \sqrt {a+b x^4}}{10 b^{5/2} \left (\sqrt {a}+\sqrt {b} x^2\right )}+\frac {21 a^{5/4} \left (\sqrt {a}+\sqrt {b} x^2\right ) \sqrt {\frac {a+b x^4}{\left (\sqrt {a}+\sqrt {b} x^2\right )^2}} E\left (2 \arctan \left (\frac {\sqrt [4]{b} x}{\sqrt [4]{a}}\right )|\frac {1}{2}\right )}{10 b^{11/4} \sqrt {a+b x^4}}-\frac {21 a^{5/4} \left (\sqrt {a}+\sqrt {b} x^2\right ) \sqrt {\frac {a+b x^4}{\left (\sqrt {a}+\sqrt {b} x^2\right )^2}} \operatorname {EllipticF}\left (2 \arctan \left (\frac {\sqrt [4]{b} x}{\sqrt [4]{a}}\right ),\frac {1}{2}\right )}{20 b^{11/4} \sqrt {a+b x^4}} \]
[Out]
Time = 0.07 (sec) , antiderivative size = 258, normalized size of antiderivative = 1.00, number of steps used = 5, number of rules used = 5, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.333, Rules used = {294, 327, 311, 226, 1210} \[ \int \frac {x^{10}}{\left (a+b x^4\right )^{3/2}} \, dx=-\frac {21 a^{5/4} \left (\sqrt {a}+\sqrt {b} x^2\right ) \sqrt {\frac {a+b x^4}{\left (\sqrt {a}+\sqrt {b} x^2\right )^2}} \operatorname {EllipticF}\left (2 \arctan \left (\frac {\sqrt [4]{b} x}{\sqrt [4]{a}}\right ),\frac {1}{2}\right )}{20 b^{11/4} \sqrt {a+b x^4}}+\frac {21 a^{5/4} \left (\sqrt {a}+\sqrt {b} x^2\right ) \sqrt {\frac {a+b x^4}{\left (\sqrt {a}+\sqrt {b} x^2\right )^2}} E\left (2 \arctan \left (\frac {\sqrt [4]{b} x}{\sqrt [4]{a}}\right )|\frac {1}{2}\right )}{10 b^{11/4} \sqrt {a+b x^4}}-\frac {21 a x \sqrt {a+b x^4}}{10 b^{5/2} \left (\sqrt {a}+\sqrt {b} x^2\right )}+\frac {7 x^3 \sqrt {a+b x^4}}{10 b^2}-\frac {x^7}{2 b \sqrt {a+b x^4}} \]
[In]
[Out]
Rule 226
Rule 294
Rule 311
Rule 327
Rule 1210
Rubi steps \begin{align*} \text {integral}& = -\frac {x^7}{2 b \sqrt {a+b x^4}}+\frac {7 \int \frac {x^6}{\sqrt {a+b x^4}} \, dx}{2 b} \\ & = -\frac {x^7}{2 b \sqrt {a+b x^4}}+\frac {7 x^3 \sqrt {a+b x^4}}{10 b^2}-\frac {(21 a) \int \frac {x^2}{\sqrt {a+b x^4}} \, dx}{10 b^2} \\ & = -\frac {x^7}{2 b \sqrt {a+b x^4}}+\frac {7 x^3 \sqrt {a+b x^4}}{10 b^2}-\frac {\left (21 a^{3/2}\right ) \int \frac {1}{\sqrt {a+b x^4}} \, dx}{10 b^{5/2}}+\frac {\left (21 a^{3/2}\right ) \int \frac {1-\frac {\sqrt {b} x^2}{\sqrt {a}}}{\sqrt {a+b x^4}} \, dx}{10 b^{5/2}} \\ & = -\frac {x^7}{2 b \sqrt {a+b x^4}}+\frac {7 x^3 \sqrt {a+b x^4}}{10 b^2}-\frac {21 a x \sqrt {a+b x^4}}{10 b^{5/2} \left (\sqrt {a}+\sqrt {b} x^2\right )}+\frac {21 a^{5/4} \left (\sqrt {a}+\sqrt {b} x^2\right ) \sqrt {\frac {a+b x^4}{\left (\sqrt {a}+\sqrt {b} x^2\right )^2}} E\left (2 \tan ^{-1}\left (\frac {\sqrt [4]{b} x}{\sqrt [4]{a}}\right )|\frac {1}{2}\right )}{10 b^{11/4} \sqrt {a+b x^4}}-\frac {21 a^{5/4} \left (\sqrt {a}+\sqrt {b} x^2\right ) \sqrt {\frac {a+b x^4}{\left (\sqrt {a}+\sqrt {b} x^2\right )^2}} F\left (2 \tan ^{-1}\left (\frac {\sqrt [4]{b} x}{\sqrt [4]{a}}\right )|\frac {1}{2}\right )}{20 b^{11/4} \sqrt {a+b x^4}} \\ \end{align*}
Result contains higher order function than in optimal. Order 5 vs. order 4 in optimal.
Time = 10.03 (sec) , antiderivative size = 66, normalized size of antiderivative = 0.26 \[ \int \frac {x^{10}}{\left (a+b x^4\right )^{3/2}} \, dx=\frac {x^3 \left (-7 a+b x^4+7 a \sqrt {1+\frac {b x^4}{a}} \operatorname {Hypergeometric2F1}\left (\frac {3}{4},\frac {3}{2},\frac {7}{4},-\frac {b x^4}{a}\right )\right )}{5 b^2 \sqrt {a+b x^4}} \]
[In]
[Out]
Result contains complex when optimal does not.
Time = 5.58 (sec) , antiderivative size = 137, normalized size of antiderivative = 0.53
method | result | size |
default | \(\frac {a \,x^{3}}{2 b^{2} \sqrt {\left (x^{4}+\frac {a}{b}\right ) b}}+\frac {x^{3} \sqrt {b \,x^{4}+a}}{5 b^{2}}-\frac {21 i a^{\frac {3}{2}} \sqrt {1-\frac {i \sqrt {b}\, x^{2}}{\sqrt {a}}}\, \sqrt {1+\frac {i \sqrt {b}\, x^{2}}{\sqrt {a}}}\, \left (F\left (x \sqrt {\frac {i \sqrt {b}}{\sqrt {a}}}, i\right )-E\left (x \sqrt {\frac {i \sqrt {b}}{\sqrt {a}}}, i\right )\right )}{10 b^{\frac {5}{2}} \sqrt {\frac {i \sqrt {b}}{\sqrt {a}}}\, \sqrt {b \,x^{4}+a}}\) | \(137\) |
elliptic | \(\frac {a \,x^{3}}{2 b^{2} \sqrt {\left (x^{4}+\frac {a}{b}\right ) b}}+\frac {x^{3} \sqrt {b \,x^{4}+a}}{5 b^{2}}-\frac {21 i a^{\frac {3}{2}} \sqrt {1-\frac {i \sqrt {b}\, x^{2}}{\sqrt {a}}}\, \sqrt {1+\frac {i \sqrt {b}\, x^{2}}{\sqrt {a}}}\, \left (F\left (x \sqrt {\frac {i \sqrt {b}}{\sqrt {a}}}, i\right )-E\left (x \sqrt {\frac {i \sqrt {b}}{\sqrt {a}}}, i\right )\right )}{10 b^{\frac {5}{2}} \sqrt {\frac {i \sqrt {b}}{\sqrt {a}}}\, \sqrt {b \,x^{4}+a}}\) | \(137\) |
risch | \(\frac {x^{3} \sqrt {b \,x^{4}+a}}{5 b^{2}}-\frac {a \left (8 b \left (-\frac {x^{3}}{2 b \sqrt {\left (x^{4}+\frac {a}{b}\right ) b}}+\frac {3 i \sqrt {a}\, \sqrt {1-\frac {i \sqrt {b}\, x^{2}}{\sqrt {a}}}\, \sqrt {1+\frac {i \sqrt {b}\, x^{2}}{\sqrt {a}}}\, \left (F\left (x \sqrt {\frac {i \sqrt {b}}{\sqrt {a}}}, i\right )-E\left (x \sqrt {\frac {i \sqrt {b}}{\sqrt {a}}}, i\right )\right )}{2 b^{\frac {3}{2}} \sqrt {\frac {i \sqrt {b}}{\sqrt {a}}}\, \sqrt {b \,x^{4}+a}}\right )+3 a \left (\frac {x^{3}}{2 a \sqrt {\left (x^{4}+\frac {a}{b}\right ) b}}-\frac {i \sqrt {1-\frac {i \sqrt {b}\, x^{2}}{\sqrt {a}}}\, \sqrt {1+\frac {i \sqrt {b}\, x^{2}}{\sqrt {a}}}\, \left (F\left (x \sqrt {\frac {i \sqrt {b}}{\sqrt {a}}}, i\right )-E\left (x \sqrt {\frac {i \sqrt {b}}{\sqrt {a}}}, i\right )\right )}{2 \sqrt {a}\, \sqrt {\frac {i \sqrt {b}}{\sqrt {a}}}\, \sqrt {b \,x^{4}+a}\, \sqrt {b}}\right )\right )}{5 b^{2}}\) | \(268\) |
[In]
[Out]
none
Time = 0.10 (sec) , antiderivative size = 131, normalized size of antiderivative = 0.51 \[ \int \frac {x^{10}}{\left (a+b x^4\right )^{3/2}} \, dx=-\frac {21 \, {\left (a b x^{5} + a^{2} x\right )} \sqrt {b} \left (-\frac {a}{b}\right )^{\frac {3}{4}} E(\arcsin \left (\frac {\left (-\frac {a}{b}\right )^{\frac {1}{4}}}{x}\right )\,|\,-1) - 21 \, {\left (a b x^{5} + a^{2} x\right )} \sqrt {b} \left (-\frac {a}{b}\right )^{\frac {3}{4}} F(\arcsin \left (\frac {\left (-\frac {a}{b}\right )^{\frac {1}{4}}}{x}\right )\,|\,-1) - {\left (2 \, b^{2} x^{8} - 14 \, a b x^{4} - 21 \, a^{2}\right )} \sqrt {b x^{4} + a}}{10 \, {\left (b^{4} x^{5} + a b^{3} x\right )}} \]
[In]
[Out]
Result contains complex when optimal does not.
Time = 0.61 (sec) , antiderivative size = 37, normalized size of antiderivative = 0.14 \[ \int \frac {x^{10}}{\left (a+b x^4\right )^{3/2}} \, dx=\frac {x^{11} \Gamma \left (\frac {11}{4}\right ) {{}_{2}F_{1}\left (\begin {matrix} \frac {3}{2}, \frac {11}{4} \\ \frac {15}{4} \end {matrix}\middle | {\frac {b x^{4} e^{i \pi }}{a}} \right )}}{4 a^{\frac {3}{2}} \Gamma \left (\frac {15}{4}\right )} \]
[In]
[Out]
\[ \int \frac {x^{10}}{\left (a+b x^4\right )^{3/2}} \, dx=\int { \frac {x^{10}}{{\left (b x^{4} + a\right )}^{\frac {3}{2}}} \,d x } \]
[In]
[Out]
\[ \int \frac {x^{10}}{\left (a+b x^4\right )^{3/2}} \, dx=\int { \frac {x^{10}}{{\left (b x^{4} + a\right )}^{\frac {3}{2}}} \,d x } \]
[In]
[Out]
Timed out. \[ \int \frac {x^{10}}{\left (a+b x^4\right )^{3/2}} \, dx=\int \frac {x^{10}}{{\left (b\,x^4+a\right )}^{3/2}} \,d x \]
[In]
[Out]